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1870 Nebraska gubernatorial election

1870 Nebraska gubernatorial election

← 1868 October 11, 1870 1872 →
 
Nominee David Butler John H. Croxton
Party Republican Democratic
Popular vote 11,126 8,648
Percentage 56.3% 43.7%

County results
Butler:      50–60%      60–70%      70–80%      80–90%      90–100%
Croxton:      50–60%      60–70%      70–80%
No Data/Votes:      

Governor before election

David Butler
Republican

Elected Governor

David Butler
Republican

The 1870 Nebraska gubernatorial election was held on October 11, 1870.[a] Two-term incumbent Governor of Nebraska David Butler, the Republican nominee, was seeking a third term as governor. He was opposed by Democratic nominee John H. Croxton, a lawyer from Nebraska City.[3]

  1. ^ "Nebraska Constitution of 1866, Article III, Section 1". 1866. The Executive Department shall consist of a Governor, Secretary of State, Auditor and Treasurer, who shall be chosen by the electors of the State on the second Tuesday of October....
  2. ^ "A Defense of Mr. Tipton". Brownville Daily Democrat. October 4, 1870. Retrieved June 21, 2023. Let the verdict at the polls on the 11th of October answer the question.
  3. ^ Cite error: The named reference results was invoked but never defined (see the help page).


Cite error: There are <ref group=lower-alpha> tags or {{efn}} templates on this page, but the references will not show without a {{reflist|group=lower-alpha}} template or {{notelist}} template (see the help page).


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