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Dunreith, Indiana
Town of Dunreith, Indiana | |
|---|---|
 Location of Dunreith in Henry County, Indiana. | |
| Coordinates: 39°48′10″N 85°26′12″W / 39.80278°N 85.43667°W | |
| Country | United States |
| State | Indiana |
| County | Henry |
| Township | Spiceland |
| Area | |
• Total | 0.12 sq mi (0.32 km2) |
| • Land | 0.12 sq mi (0.32 km2) |
| • Water | 0.00 sq mi (0.00 km2) |
| Elevation | 1,040 ft (320 m) |
| Population (2020) | |
• Total | 171 |
• Estimate (2025) | 172[3]  |
| • Density | 1,379.03/sq mi (530.48/km2) |
| Time zone | UTC-5 (EST) |
| • Summer (DST) | UTC-4 (EDT[4]) |
| ZIP code | 47337 |
| Area code | 765 |
| FIPS code | 18-19162[5] |
| GNIS feature ID | 2396912[2] |
Dunreith is a town in Spiceland Township, Henry County, Indiana, United States. The population was 171 at the 2020 census.
- ^ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
- ^ a b U.S. Geological Survey Geographic Names Information System: Dunreith, Indiana
- ^ Cite error: The named reference
IndianaDemographicswas invoked but never defined (see the help page). - ^ Dunreith, Indiana Current Local Time. timetemperature.com
- ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
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