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Shueyville, Iowa
Shueyville, Iowa | |
|---|---|
 | |
 Location of Shueyville, Iowa | |
| Coordinates: 41°50′53″N 91°38′55″W / 41.84806°N 91.64861°W | |
| Country |  United States |
| State |  Iowa |
| County | Johnson |
| Area | |
• Total | 1.86 sq mi (4.83 km2) |
| • Land | 1.86 sq mi (4.83 km2) |
| • Water | 0.00 sq mi (0.00 km2) |
| Elevation | 801 ft (244 m) |
| Population (2020) | |
• Total | 731 |
| • Density | 392.17/sq mi (151.45/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| FIPS code | 19-72840 |
| GNIS feature ID | 0461591 |
Shueyville is a city in Johnson County, Iowa, United States. It is part of the Iowa City, Iowa Metropolitan Statistical Area. The population was 731 at the time of the 2020 census.[2]
- ^ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
- ^ "2020 Census State Redistricting Data". census.gov. United states Census Bureau. Retrieved August 12, 2021.
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