1866 Vermont gubernatorial election

1866 Vermont gubernatorial election

← 1865 September 4, 1866 (1866-09-04) 1867 →
 
Candidate Paul Dillingham Charles N. Davenport
Party Republican Democratic
Popular vote 34,117 11,292
Percentage 75.1 24.9

County results
Dillingham:      60–70%      70–80%      80–90%      >90%

Governor before election

Paul Dillingham
Republican

Elected Governor

Paul Dillingham
Republican

The 1866 Vermont gubernatorial election took place on September 4, 1866.[1] In keeping with the "Mountain Rule",[2] Incumbent Republican Paul Dillingham was a candidate for a second one-year term as governor of Vermont.[3] With the election taking place soon after the American Civil War, Dillingham ran as a pro-Union Republican.[4] The Democratic nomination was won by Charles N. Davenport of Wilmington, an attorney and founder of the Brattleboro Reformer newspaper, who was also the Democratic nominee in 1865.[5][6] In the general election, Dillingham was easily elected to a second one-year term as governor.[7]

  1. ^ "Latest News: Vermont Elections". Rutland Herald. Rutland, VT. September 5, 1866. p. 1 – via Newspapers.com.
  2. ^ Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved January 5, 2016.
  3. ^ "Republican State Ticket". Burlington Free Press. Burlington, VT. June 22, 1866. p. 2 – via Newspapers.com.
  4. ^ "Union State Nominations". The Vermont Phoenix. Brattleboro, VT. August 31, 1866. p. 2 – via Newspapers.com.
  5. ^ "Democratic State Ticket". North Star. Danville, VT. September 1, 1866. p. 3 – via Newspapers.com.
  6. ^ Walbridge, J. H. (1900). Wilmington, Vermont. Wilmington, VT: Deerfield Valley Times Press. p. 21 – via Google Books.
  7. ^ "1866 Governor General Election". Vermont Elections Database. Montpelier, VT: Vermont Secretary of State. Retrieved June 10, 2020.

1866 Vermont gubernatorial election

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