1910 Iowa Senate election

1910 Iowa Senate election

← 1908 November 8, 1910 1912 →

22 out of 50 seats in the Iowa State Senate
26 seats needed for a majority
  Majority party Minority party
 
Party Republican Democratic
Last election 34 16
Seats after 34 16
Seat change Steady Steady

Results
     Democratic gain      Republican gain
     Democratic hold      Republican hold

The 1910 Iowa State Senate elections took place as part of the biennial 1910 United States elections. Iowa voters elected state senators in 22 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.

A statewide map of the 50 state Senate districts in the 1910 elections is provided by the Iowa General Assembly here.

The primary election on June 7, 1910, determined which candidates appeared on the November 8, 1910 general election ballot.[1][2]

Following the previous election, Republicans had control of the Iowa Senate with 34 seats to Democrats' 16 seats.

To claim control of the chamber from Republicans, the Democrats needed to net 10 Senate seats.

Republicans maintained control of the Iowa State Senate following the 1910 general election with the balance of power remaining unchanged with Republicans holding 34 seats and Democrats having 16 seats.

  1. ^ "Primary Election 1910 For State Senator" (PDF). Iowa Official Register. Retrieved June 16, 2021.
  2. ^ "General Election 1910 For State Senator" (PDF). Iowa Official Register. Retrieved June 16, 2021.

1910 Iowa Senate election

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