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22 out of 50 seats in the Iowa State Senate 26 seats needed for a majority | |||||||||||||||||||
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Results Democratic gain Republican gain Democratic hold Republican hold |
Elections in Iowa |
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The 1910 Iowa State Senate elections took place as part of the biennial 1910 United States elections. Iowa voters elected state senators in 22 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.
A statewide map of the 50 state Senate districts in the 1910 elections is provided by the Iowa General Assembly here.
The primary election on June 7, 1910, determined which candidates appeared on the November 8, 1910 general election ballot.[1][2]
Following the previous election, Republicans had control of the Iowa Senate with 34 seats to Democrats' 16 seats.
To claim control of the chamber from Republicans, the Democrats needed to net 10 Senate seats.
Republicans maintained control of the Iowa State Senate following the 1910 general election with the balance of power remaining unchanged with Republicans holding 34 seats and Democrats having 16 seats.